Kopertina e librit Matematika 10 - 11: Pjesa I

Zgjidhja e ushtrimit 5

Zgjidhja e ushtrimit 5 të mësimit 9.1A në librin Matematika 10 - 11: Pjesa I nga shtëpia botuese Botime Pegi me autorë Steve Fearnley, June Haighton, Steve Lomax, Peter Mullarkey, James Nicholson dhe Matt Nixon.

Pyetja

Gjeni një përfundim të përafërt për secilën nga llogaritjet e mëposhtme.

  1. 317×4.220.197\dfrac{317 \times 4.22}{0.197}
  2. 4.37×6890.793\dfrac{4.37 \times 689}{0.793}
  3. 4.75×122522×0.38\dfrac{4.75 \times 122}{522 \times 0.38}
  4. 4.83−8.524.8^3 - 8.5^2
  5. 9.32−3.850.043−0.021\dfrac{9.32 - 3.85}{0.043 - 0.021}
  6. 7.73×(9.32−3.850.043−0.021)7.73 \times (\dfrac{9.32 - 3.85}{0.043 - 0.021})
  7. 48.75×4.9710.132\dfrac{48.75 \times 4.97}{10.13^2}
  8. 305.32913\sqrt{\dfrac{305.3^2}{913}}
  9. 9.67×8.830.087\dfrac{\sqrt{9.67 \times 8.83}}{0.087}
  10. 6.82+11.8247.8×52.1\dfrac{6.8^2 + 11.8^2}{\sqrt{47.8 \times 52.1}}
  11. (23.4−18.2)23.2+1.8\dfrac{(23.4-18.2)^2}{3.2+1.8}
  12. 2.85+5.910.172\sqrt{\dfrac{2.85+5.91}{0.17^2}}

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Zgjidhja

  1. 300×40.2=6000\dfrac{300 \times 4}{0.2} = 6000
  2. 4×7000.8=3500\dfrac{4 \times 700}{0.8} = 3500
  3. 5×100500×0.4=500200=2.5\dfrac{5 \times 100}{500 \times 0.4} = \dfrac{500}{200} = 2.5
  4. 53−92=125−81=445^3 - 9^2 = 125-81=44
  5. 9−40.04−0.02=50.02=250\dfrac{9-4}{0.04-0.02} = \dfrac{5}{0.02} = 250
  6. 8×250=20008 \times 250 = 2000
  7. 50×5102=250100=2.5\dfrac{50 \times 5}{10^2} = \dfrac{250}{100} = 2.5
  8. 3002900=90000900=100=10\sqrt{\dfrac{300^2}{900}} = \sqrt{\dfrac{90000}{900}} = \sqrt{100}=10
  9. 9×90.09=90.09=100\dfrac{\sqrt{9 \times 9}}{0.09} = \dfrac{9}{0.09} = 100
  10. 72+12250×50=49+14450=19350=3.86\dfrac{7^2 + 12^2}{\sqrt{50 \times 50}} = \dfrac{49+144}{50} = \dfrac{193}{50} = 3.86
  11. 525=5\dfrac{5^2}{5} = 5
  12. 90.22=90.04=225=15\sqrt{\dfrac{9}{0.2^2}} = \sqrt{\dfrac{9}{0.04}} = \sqrt{225} = 15