Pyetja
Zgjidh ekuacionet e mëposhtme, në intervalet e dhëna.
- $\sin 2\theta = \sin \theta$, $0 \le \theta \le 2\pi$
- $\cos 2\theta = 1 - \cos \theta$, $-180^{\circ} < \theta \le 180^{\circ}$
- $3 \cos 2\theta = 2 \cos^2 \theta$, $0 \le \theta < 360^{\circ}$
- $\sin 4\theta = \cos 2\theta$, $0 \le \theta \le \pi$
- $3 \cos \theta - \sin \frac{\theta}{2} - 1 = 0$, $0 \le \theta < 720^{\circ}$
- $\cos^2 \theta - \sin 2\theta = \sin^2 \theta$, $0 \le \theta \le \pi$
- $2 \sin \theta = \sec \theta$, $0 \le \theta \le 2\pi$
- $2 \sin 2\theta = 3 \tan \theta$, $0 \le \theta < 360^{\circ}$
- $2 \tan \theta = \sqrt{3}(1 - \tan \theta)(1 + \tan \theta)$, $0 \le \theta \le 2\pi$
- $\sin^2 \theta = 2 \sin 2\theta$, $-180^{\circ} < \theta < 180^{\circ}$
- $4 \tan \theta = \tan 2\theta$, $0 \le \theta \le 360^{\circ}$
