Thjeshto këto thyesa plotësisht:
- (x−2)(x+3)(x−2)
- (3x−1)(x+4)(3x−1)
- (x+3)(x+3)2
- (x+3)x2+10x+21
- (x+4)x2+9x+20
- (x−3)x2+x−12
- x2+2x−15x2+x−20
- x2+5x+4x2+3x+2
- x2−9x+18x2+x−12
- (x−5)(x+2)2x2+7x+6
- (x+6)(x+1)2x2+9x−18
- (3x−1)(x+2)3x2−7x+2
- x2−x−22x2+3x+1
- 3x2+7x+2x2+6x+8
- 2x2−9x+92x2−5x−3