Zgjidhja e ushtrimit 11

Si fillim, kthejmë numrat e përzier në thyesa të parregullta dhe më pas kryejmë veprimet.

1. $\dfrac{3}{2} \times \dfrac{3}{4} = \dfrac{3 \times 3}{2 \times 4} = \dfrac{9}{8} = 1\dfrac{1}{8}$
2. $\dfrac{11}{4} \times \dfrac{2}{5} = \dfrac{11 \times \cancel{2}}{\cancel{4} \times 5} = \dfrac{11 \times 1}{2 \times 5} = \dfrac{11}{10} = 1\dfrac{1}{10}$
3. $\dfrac{6}{5} \times \dfrac{11}{5} = \dfrac{6 \times 11}{5 \times 5} = \dfrac{66}{25} = 2\dfrac{16}{25}$
4. $\dfrac{5}{3} \times \dfrac{9}{5} = \dfrac{\cancel{5} \times \cancel{9}}{\cancel{3} \times \cancel{5}} = \dfrac{1 \times 3}{1 \times 1} = 3$
5. $\dfrac{23}{8} \times \dfrac{5}{3} = \dfrac{23 \times 5}{8 \times 3} = \dfrac{115}{24} = 4\dfrac{19}{24}$
6. $\dfrac{17}{4} : \dfrac{7}{2} = \dfrac{17}{\cancel{4}} \times \dfrac{\cancel{2}}{7} = \dfrac{17 \times 1}{2 \times 7} = \dfrac{17}{14} = 1\dfrac{3}{14}$
7. $\dfrac{43}{8} : \dfrac{11}{4} = \dfrac{43}{\cancel{8}} \times \dfrac{\cancel{4}}{11} = \dfrac{43 \times 1}{2 \times 11} = \dfrac{43}{22} = 1\dfrac{21}{22}$
8. $\dfrac{28}{3} : \dfrac{9}{4} = \dfrac{28}{3} \times \dfrac{4}{9} = \dfrac{28 \times 4}{3 \times 9} = \dfrac{112}{27} = 4\dfrac{4}{27}$