Kopertina e librit Matematika 10 - 11: Pjesa II

Zgjidhja e ushtrimit 3

Zgjidhja e ushtrimit 3 të mësimit 5.2A në librin Matematika 10 - 11: Pjesa II nga shtëpia botuese Botime Pegi me autorë Steve Fearnley, June Haighton, Steve Lomax, Peter Mullarkey, James Nicholson dhe Matt Nixon.


Pyetja

Kryeni veprimet me saktësi:

  1. 23×34\dfrac{2}{3} \times \dfrac{3}{4}
  2. 59:13\dfrac{5}{9} : \dfrac{1}{3}
  3. 212×582\dfrac{1}{2} \times \dfrac{5}{8}
  4. 89:123\dfrac{8}{9} : 1\dfrac{2}{3}
  5. 312:2143\dfrac{1}{2} : 2\dfrac{1}{4}
  6. 515×2345\dfrac{1}{5} \times 2\dfrac{3}{4}

Zgjidhja

  1. 23×34=24=12\dfrac{2}{\cancel{3}} \times \dfrac{\cancel{3}}{4} = \dfrac{2}{4} = \dfrac{1}{2}
  2. 59×3=53\dfrac{5}{\cancel{9}} \times \cancel{3} = \dfrac{5}{3}
  3. 52×58=2516\dfrac{5}{2} \times \dfrac{5}{8} = \dfrac{25}{16} == 19161\dfrac{9}{16}
  4. 89×35=815\dfrac{8}{\cancel{9}} \times \dfrac{\cancel{3}}{5} = \dfrac{8}{15}
  5. 72:94=72×49=149\dfrac{7}{2} : \dfrac{9}{4} = \dfrac{7}{\cancel{2}} \times \dfrac{\cancel{4}}{9} = \dfrac{14}{9} == 1591\dfrac{5}{9}
  6. 265×114=28620=14310\dfrac{26}{5} \times \dfrac{11}{4} = \dfrac{286}{20} = \dfrac{143}{10}