Kopertina e librit Matematika 10 - 11: Pjesa II

Zgjidhja e ushtrimit 5

Zgjidhja e ushtrimit 5 të mësimit Përsëritje 5 në librin Matematika 10 - 11: Pjesa II nga shtëpia botuese Botime Pegi me autorë Steve Fearnley, June Haighton, Steve Lomax, Peter Mullarkey, James Nicholson dhe Matt Nixon.

Pyetja

Gjeni vlerën e saktë të shprehjeve të mëposhtme.

  1. 514×8\dfrac{5}{14} \times 8
  2. 59×320\dfrac{5}{9} \times \dfrac{3}{20}
  3. 715+23\dfrac{7}{15} + \dfrac{2}{3}
  4. 67−38\dfrac{6}{7} - \dfrac{3}{8}
  5. 515−1135\dfrac{1}{5} - 1\dfrac{1}{3}
  6. 813×358\dfrac{1}{3} \times \dfrac{3}{5}
  7. 611:9\dfrac{6}{11} : 9
  8. 314:97\dfrac{3}{14} : \dfrac{9}{7}
  9. 214:3132\dfrac{1}{4} : 3\dfrac{1}{3}

Dëshiron të blesh libra manga?

Kliko këtu për të parë ofertat e Kleptobuk

Zgjidhja

  1. 8×514=4014=207=267\dfrac{8 \times 5}{14} = \dfrac{40}{14} = \dfrac{20}{7} = 2\dfrac{6}{7}
  2. 59×320=13×14=112\dfrac{\cancel5}{\cancel9} \times \dfrac{\cancel3}{\cancel{20}} = \dfrac{1}{3} \times \dfrac{1}{4} = \dfrac{1}{12}
  3. 7+(2×5)15=7+1015=1715=1215\dfrac{7 + (2 \times 5)}{15} = \dfrac{7 + 10}{15} = \dfrac{17}{15} = 1\dfrac{2}{15}
  4. 6×856−3×756=4856−2156=2756\dfrac{6 \times 8}{56} - \dfrac{3 \times 7}{56} = \dfrac{48}{56} - \dfrac{21}{56} = \dfrac{27}{56}
  5. (5×5)+15−(3×1)+13=265−43=(26×3)−(4×5)15=78−2015=5815=31315\dfrac{(5 \times 5) + 1}{5} - \dfrac{(3 \times 1) + 1}{3} = \dfrac{26}{5} - \dfrac{4}{3} = \dfrac{(26 \times 3) - (4 \times 5)}{15} = \dfrac{78 - 20}{15} = \dfrac{58}{15} = 3\dfrac{13}{15}
  6. (3×8)+13×35=253×35=5×1=5\dfrac{(3 \times 8) + 1}{3} \times \dfrac{3}{5} = \dfrac{\cancel{25}}{\cancel3} \times \dfrac{\cancel3}{\cancel5} = 5 \times 1 = 5
  7. 611×19=211×3=233\dfrac{\cancel{6}}{11} \times \dfrac{1}{\cancel9} = \dfrac{2}{11 \times 3} = \dfrac{2}{33}
  8. 314×79=12×3=16\dfrac{\cancel3}{\cancel{14}} \times \dfrac{\cancel7}{\cancel9} = \dfrac{1}{2 \times 3} = \dfrac{1}{6}
  9. (4×2)+14:(3×3)+13=94:103=94×310=2740\dfrac{(4 \times 2) + 1}{4} : \dfrac{(3 \times 3) + 1}{3} = \dfrac{9}{4} : \dfrac{10}{3} = \dfrac{9}{4} \times \dfrac{3}{10} = \dfrac{27}{40}