Pyetja
Zgjidh ekuacionet e mëposhtme në intervalet e dhëna.
- $sec^2 \theta = 3 tan \theta$, $0 \le \theta \le 360^\circ$
- $tan^2 \theta - 2 sec \theta + 1 = 0$, $-\pi \le \theta \le \pi$
- $cosec^2 \theta + 1 = 3 cot \theta$, $-180^\circ \le \theta \le 180^\circ$
- $cot \theta = 1 - cosec^2 \theta$, $0 \le \theta \le 2\pi$
- $3 sec \frac{1}{2}\theta = 2 tan^2 \frac{1}{2}\theta$, $0 \le \theta \le 360^\circ$
- $(sec \theta - cos \theta)^2 = tan \theta - sin^2 \theta$, $0 \le \theta \le \pi$
- $tan^2 2\theta = sec 2\theta - 1$, $0 \le \theta \le 180^\circ$
- $sec^2 \theta - (1 + \sqrt{3}) tan \theta + \sqrt{3} = 1$, $0 \le \theta \le 2\pi$
